document.write( "Question 1066248: two workers a and b together could finish the work in 8 days.they worked together for six days and a left the work.the remaining work was completed by b alone in 6 days.how many days would each take?
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Algebra.Com's Answer #681455 by jorel1380(3719) $\"\"$ $\"About$

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If we have two workers, a & b, finishing a job in 8 days, then:
\n" ); document.write( "1/a + 1/b=1/8
\n" ); document.write( "They both work six days, so:
\n" ); document.write( "6/a + 6/b=6/8=3/4
\n" ); document.write( "This leaves 1/4 of the work to be done, which b does in 6 days, so:
\n" ); document.write( "6/b=1/4
\n" ); document.write( "b=24
\n" ); document.write( "1/8-1/24=1/a
\n" ); document.write( "3/24-1/24=1/a
\n" ); document.write( "2a=24
\n" ); document.write( "a=12
\n" ); document.write( "a alone would take 12 days to finish the job, b would take 24 days working alone. ☺☺☺☺ \n" ); document.write( "

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