document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=93571>Question 93571</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you solve by factoring the quadratic\r<BR>\n" );
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document.write( "5y³ + 34y² = 7y \r<BR>\n" );
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document.write( "and show every step? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #68144 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=68144\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> factor the quadratic 5y^3+34y^2=7y <BR>\n" );
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document.write( "It's a cubic equation.<BR>\n" );
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document.write( "Rearrange to get:<BR>\n" );
document.write( "5y^3+34y^2-7y = 0<BR>\n" );
document.write( "You have a common factor of \"y\".<BR>\n" );
document.write( "y(5y^2+34y-7)=0<BR>\n" );
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document.write( "To factor 5y^2+34y-7 use the AC Method:<BR>\n" );
document.write( "Think of two integers whose product = AC = 5*-7 = -35<BR>\n" );
document.write( "and whose sum is B = 34.<BR>\n" );
document.write( "The numbers are 35 and -1<BR>\n" );
document.write( "Rewrite the quadratic as:<BR>\n" );
document.write( "5y^2+35y-y-7<BR>\n" );
document.write( "Factor the 1st two and the last two terms separately to get:<BR>\n" );
document.write( "5y(y+7)-(y+7)<BR>\n" );
document.write( "Factor again to get:<BR>\n" );
document.write( "(y+7)(5y-1)<BR>\n" );
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document.write( "So, y(y+7)(5y-1)=0<BR>\n" );
document.write( "You have factored the problem.<BR>\n" );
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document.write( "If you want to \"solve\" the equation you get:<BR>\n" );
document.write( "y=0 or y=-7 or y=1/5<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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