document.write( "Question 1066254: 9x^2+25y^2=40.........(1)
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Algebra.Com's Answer #681434 by ikleyn(52800)\"\" \"About 
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document.write( "\"9x%5E2%2B25y%5E2\" = 40     (1)\r\n" );
document.write( "\"3x%2B5y\" = 6         (2)\r\n" );
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document.write( "Express 3x = 6 - 5y from (2) and then substitute it into (1), replacing \"9x%5E2\" = \"%283x%29%5E2\"  (!!).  You will get\r\n" );
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document.write( "\"%286-5y%29%5E2+%2B+25y%5E2\" = 40,\r\n" );
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document.write( "\"36+-+60y+%2B+25y%5E2+%2B+25y%5E2\" = 40,\r\n" );
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document.write( "\"50y%5E2+-+60y+-+4\" = 0.\r\n" );
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document.write( "\"y%5B1%2C2%5D\" = \"%2860+%2B-+sqrt%283600+%2B+4%2A4%2A50%29%29%2F100\" = \"%2860+%2B-+10%2Asqrt%2844%29%29%2F100\" = \"0.6+%2B-+0.2%2Asqrt%2811%29\".\r\n" );
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document.write( "Thus,  one solution is \"y%5B1%5D\" = \"0.6+%2B+0.2%2Asqrt%2811%29\", \"x%5B1%5D\" = \"%286-5y%5B1%5D%29%2F3\" = \"%283+-+sqrt%2811%29%29%2F3\".\r\n" );
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document.write( "The second solution is \"y%5B2%5D\" = \"0.6+-+0.2%2Asqrt%2811%29\", \"x%5B2%5D\" = \"%286-5y%5B2%5D%29%2F3\" = \"%283%2Bsqrt%2811%29%29%2F3\".\r\n" );
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