document.write( "Question 1066193: One airplane costs four times as much as a certain car. Two such planes cost $6000 more than six of the cars. Find the cost of each? \n" ); document.write( "

Algebra.Com's Answer #681390 by addingup(3677) $\"\"$ $\"About$

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p = 4c
\n" ); document.write( "2p = 6c+6000 substitute for p:
\n" ); document.write( "2(4c) = 6c+6,000
\n" ); document.write( "8c = 6c+6,000
\n" ); document.write( "2c = 6,000
\n" ); document.write( "c = 3,000
\n" ); document.write( "so the cars cost 3,000 each.
\n" ); document.write( "And the planes, the problem says p = 4c, thus p = 4(3,000), p = 12,000 each plane costs 12,000 \n" ); document.write( "

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