document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1066182>Question 1066182</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find x so the distance between (x,2) and (2x+1,5) is 5<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #681346 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=681346\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Distance is the sqrt (sum of the squared differences)= sqrt ((1.5-2)^2+x^2)=5, and squaring both sides means .5^2+x^2=x^2+.25=25<BR>\n" );
document.write( "x^2=24.75<BR>\n" );
document.write( "x=4.97<BR>\n" );
document.write( "(4.97,2) and (9.94, 1.5)<BR>\n" );
document.write( "The distance is sqrt (.5^2+4.97^2)=sqrt (.25+24.70)=sqrt (24.95)=5 with rounding. </SPAN>\n" );
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