document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=93548>Question 93548</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Need to find the average of a percentage based on other variables:\r<BR>\n" );
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document.write( "I have 1 cup of apple juice that is 50% apple juice. <BR>\n" );
document.write( "I want to add 2 more cups of apple juice to the 1 cup, but it is 75% apple juice.<BR>\n" );
document.write( "What is the average percent of apple juice when I add it to the 1 cup\r<BR>\n" );
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document.write( "a=1 cup  <BR>\n" );
document.write( "(a's percentage)   a1=50%<BR>\n" );
document.write( "b=3 cups  <BR>\n" );
document.write( "(b's percentage)   b1=75%\r<BR>\n" );
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document.write( "IF a=b then you would add a1 + b1 then divide by 2   (62.5%)<BR>\n" );
document.write( "if a1=b1 then the percent of apple juice would be the same  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #68132 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=68132\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I have 1 cup of apple juice that is 50% apple juice. <BR>\n" );
document.write( "I want to add 2 more cups of apple juice to the 1 cup, but it is 75% apple juice.<BR>\n" );
document.write( "What is the average percent of apple juice when I add it to the 1 cup <BR>\n" );
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document.write( "50% juice DATA:<BR>\n" );
document.write( "Amount = 1 cup ; amt of active ingredient = 0.5 cup<BR>\n" );
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document.write( "75% juice DATA;<BR>\n" );
document.write( "Amount = 2 cups ; amt of active ingredient = (3/4)*2 = 1.5 cup<BR>\n" );
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document.write( "Mixture DATA where % is unknown:<BR>\n" );
document.write( "Amount = 3 cups ; amt of active ingredient = 3x<BR>\n" );
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document.write( "EQUATION:<BR>\n" );
document.write( "active + active = active<BR>\n" );
document.write( "0.5 + 1.5 = 3x<BR>\n" );
document.write( "2 = 3x<BR>\n" );
document.write( "x = 2/3 or 66.67 %<BR>\n" );
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document.write( "You end up with a 66.67% mixture.<BR>\n" );
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document.write( "cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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