document.write( "Question 1066116: Suppose that a cyclist began a
\n" ); document.write( "442
\n" ); document.write( "mi ride across a state at the western edge of the​ state, at the same time that a car traveling toward it leaves the eastern end of the state. If the bicycle and car met after
\n" ); document.write( "6.5
\n" ); document.write( "hr and the car traveled
\n" ); document.write( "31.4
\n" ); document.write( "mph faster than the​ bicycle, find the average rate of each.
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Algebra.Com's Answer #681306 by ankor@dixie-net.com(22740)\"\" \"About 
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Suppose that a cyclist began a 442 mi ride across a state,
\n" ); document.write( " at the western edge of the​ state, at the same time that a car traveling toward it leaves the eastern end of the state.
\n" ); document.write( " If the bicycle and car met after 6.5 hr and the car traveled 31.4 mph faster than the​ bicycle,
\n" ); document.write( " find the average rate of each.
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\n" ); document.write( "When the two meet, they will have traveled a total of 442 mi
\n" ); document.write( "let s = speed of the bike
\n" ); document.write( "then
\n" ); document.write( "(s+31.4) = speed of the car
\n" ); document.write( ":
\n" ); document.write( "Write distance equation; dist = time * speed
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\n" ); document.write( "Bike dist + Car dist = 442 mi
\n" ); document.write( "6.5s + 6.5(s+31.4) = 442
\n" ); document.write( "6.5s + 6.5s + 204.1 = 442
\n" ); document.write( "13s = 442 - 204.1
\n" ); document.write( "13s = 237.9
\n" ); document.write( "s = 237.9/13
\n" ); document.write( "s = 18.3 mph is the speed of the bike
\n" ); document.write( "and
\n" ); document.write( "18.3 + 31.4 = 49.7 mph is the speed of the car
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\n" ); document.write( "Check this by finding the actual dist each traveled:
\n" ); document.write( "18.3*6.5 = 118.95 mi
\n" ); document.write( "49.7*6.5 = 323.05
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\n" ); document.write( "total mi: 442.0 mi
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