document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1066077>Question 1066077</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Calculate S_35 for the arithmetic sequence in which a_5=19 and the common difference is d=-1.3. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #681264 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=681264\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the formula for the nth term in an arithmetic sequence is <BR>\n" );
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document.write( "a(n) = a(1) + d(n-1)<BR>\n" );
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document.write( "we are given<BR>\n" );
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document.write( "a(5) = 19 = a(1) -1.3(5-1)<BR>\n" );
document.write( "a(1) = 19 +5.2 = 24.2<BR>\n" );
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document.write( "the formula for the sum of the first nth terms of an arithmetic sequence is<BR>\n" );
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document.write( "S(n) = (n/2)(a(1) + a(n))<BR>\n" );
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document.write( "a(35) = 24.2 -1.3(35-1) = -20<BR>\n" );
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document.write( "S(35) = (35/2)(24.2 -20) = 73.5<BR>\n" );
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document.write( " </SPAN>\n" );
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