document.write( "Question 1066052: You own 7 pairs of jeans and are taking 5 on vacation. In how many ways can you choose 5 pairs of jeans from the total group?
\n" ); document.write( "Thanks for taking your time, and please don't just tell me the answer. \n" ); document.write( "

Algebra.Com's Answer #681224 by Boreal(15235) $\"\"$ $\"About$

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It is 7C5 and that is 7!/5!2!. Notice that the two on the bottom add up to the number on the top (ignore the factorial part)
\n" ); document.write( "7!=7*6*5!=42 and 42/2 is 21.
\n" ); document.write( "5!2!= -- 5! 2!=2; the 5! cancel each other.\r
\n" ); document.write( "\n" ); document.write( "Any factorial can be stopped anywhere. n!=n*(n-1)!= n(n-1)(n-2)! and so forth.
\n" ); document.write( "Notice that 7C5 and 7C2 are the same.
\n" ); document.write( "0!=1. This comes from the exponential function, whose integral defines factorial functions. It is not an arbitrary designation.
\n" ); document.write( "There are 21 ways. \n" ); document.write( "

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