document.write( "Question 1066044: Find the standard form of the equation for the circle with the following properties. Endpoints of a diameter are (8,4) and (12,-4) \n" ); document.write( "
Algebra.Com's Answer #681220 by MathTherapy(10552)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Find the standard form of the equation for the circle with the following properties. Endpoints of a diameter are (8,4) and (12,-4)
\n" ); document.write( "
Coordinates of midpoint of diameter, or center of circle: (10, 0)
\n" );
document.write( "Equation of circle: \"%28x+-+h%29%5E2+%2B+%28y+-+k%29%5E2+=+r%5E2\"
\n" );
document.write( "\"%288+-+10%29%5E2+%2B+%284+-+0%29%5E2+=+r%5E2\" ------- Substituting (8, 4) for (x, y), and (10, 0) for (h, k)
\n" );
document.write( "\"%28-+2%29%5E2+%2B+4%5E2+=+r%5E2\"
\n" );
document.write( "\"matrix%281%2C5%2C+4+%2B+16+=+r%5E2%2C+%22======%3E%22%2C+r%5E2%2C+%22=%22%2C+20%29\"
\n" );
document.write( "Equation of this circle: \"highlight_green%28%28x+-+10%29%5E2+%2B+y%5E2+=+20%29\" \n" );
document.write( "
\n" );