document.write( "Question 1066038: A random sample of 10 observations from one population revealed a sample mean of 23 and a sample standard deviation of 4. A random sample of 8 observations from another population revealed a sample mean of 26 and a sample standard deviation of 5. At the .05 significance level, is there a difference between the population means? \n" ); document.write( "
Algebra.Com's Answer #681201 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
A random sample of 10 observations from one population revealed a sample mean of 23 and a sample standard deviation of 4. A random sample of 8 observations from another population revealed a sample mean of 26 and a sample standard deviation of 5. At the .05 significance level, is there a difference between the population means?
\n" ); document.write( "-------------
\n" ); document.write( "Ho: u1-u2 = 0
\n" ); document.write( "Ha: u1-u2 # 0
\n" ); document.write( "--------------------
\n" ); document.write( "x-bar = (23-26) = -3
\n" ); document.write( "---
\n" ); document.write( "t(-3) = (-3-0)/sqrt[(4^2/10)+(5^2/8)] = -3/2.1737 = -1.3801
\n" ); document.write( "df = n2-1 = 7
\n" ); document.write( "--------------------
\n" ); document.write( "p-value = 2*P(-100< t < -1.3801) = 2*tcdf(-100,-1.3801,7) = 0.2100
\n" ); document.write( "-----
\n" ); document.write( "Since the p-value is greater than 5%, fail to reject Ho.l
\n" ); document.write( "----
\n" ); document.write( "Conclusion:: The two means are statistically equal at the
\n" ); document.write( "5% significance level.
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "---------
\n" ); document.write( "
\n" );