document.write( "Question 1066029: In a time of t hours, a particle moves a distance of s kilometers from its starting point,
\n" ); document.write( "where s = e^t∗ tan(t).\r
\n" ); document.write( "\n" ); document.write( " Find the average velocity between t = 0.25 and t = 0.25 + h if
\n" ); document.write( "(i) h = 0.01
\n" ); document.write( "(ii) h = 0.001
\n" ); document.write( "(iii) h = 0.0001
\n" ); document.write( "help me please\r
\n" ); document.write( "\n" ); document.write( "I got to
\n" ); document.write( "s(.26)- s(.25)/
\n" ); document.write( ".01
\n" ); document.write( "i dont know where to start on using s = e^t \n" ); document.write( "

Algebra.Com's Answer #681197 by Boreal(15235) $\"\"$ $\"About$

You can put this solution on YOUR website!
s=e^t+tan (t)
\n" ); document.write( "I'm assuming t is in radians.
\n" ); document.write( "e^(0.25)*tan(.25)=0.3279
\n" ); document.write( "e^0.26* tan(.26)=0.3450
\n" ); document.write( "e^0.251*tan(.251)=0.3296
\n" ); document.write( "e^0.2501*tan(.2501)=0.3280
\n" ); document.write( "so s(.26)-s(.25) all divided by 0.01 is 1.71
\n" ); document.write( "s(.251)-s(.25) divided by 0.001 is 1.69749
\n" ); document.write( "s(.2501)-s(.25) divided by 0.0001=1.69579
\n" ); document.write( "The actual derivative is tan(t)*e^t+e^t*sec^2(t)
\n" ); document.write( "this is tan(.25)*e^(0.25)*.25+e^(.25)*1/cos^2(.25)=1.69561
\n" ); document.write( " \n" ); document.write( "

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