document.write( "Question 93393: sorry wrong equation \r
\n" ); document.write( "\n" ); document.write( "log9 (1/3) = y (1/3 is NOT exponent)
\n" ); document.write( "Sorry
\n" ); document.write( "llo
\n" ); document.write( "

Algebra.Com's Answer #68116 by bucky(2189)\"\" \"About 
You can put this solution on YOUR website!
Given:
\n" ); document.write( ".
\n" ); document.write( "\"log%289%2C%281%2F3%29%29+=+y\"
\n" ); document.write( ".
\n" ); document.write( "The first thing to do is to convert this logarithmic form to the exponential form using the
\n" ); document.write( "rule:
\n" ); document.write( ".
\n" ); document.write( "\"log%28b%2CN%29+=+x\" is equivalent to \"b%5Ex+=+N\"
\n" ); document.write( ".
\n" ); document.write( "Notice that by comparing the logarithmic form of the rule to the given problem you can
\n" ); document.write( "identify x as equaling y, b as equaling 9, and N as equaling \"1%2F3\". Substitute
\n" ); document.write( "these values into the exponential form and it becomes:
\n" ); document.write( ".
\n" ); document.write( "\"9%5Ey+=+1%2F3\"
\n" ); document.write( ".
\n" ); document.write( "Now you can make a couple of changes. First, recognize that \"1%2F3\" is equivalent to
\n" ); document.write( "\"3%5E-1\".
\n" ); document.write( "Substitute this into the equation to get:
\n" ); document.write( ".
\n" ); document.write( "\"9%5Ey+=+3%5E%28-1%29\"
\n" ); document.write( ".
\n" ); document.write( "Now notice that 9 is equal to \"3%5E2\". So replace the 9 with \"3%5E2\" and you get:
\n" ); document.write( ".
\n" ); document.write( "\"%283%5E2%29%5Ey+=+3%5E%28-1%29\"
\n" ); document.write( ".
\n" ); document.write( "by the power rule of exponents you can multiply the exponent y by the exponent 2 to make the
\n" ); document.write( "left side of the equation change as indicated:
\n" ); document.write( ".
\n" ); document.write( "\"3%5E%282y%29+=+3%5E%28-1%29\"
\n" ); document.write( ".
\n" ); document.write( "Notice that the bases of the two sides are both 3. Therefore, for the sides to be equal, the
\n" ); document.write( "two exponents must also be equal. When you set the two exponents equal you get:
\n" ); document.write( ".
\n" ); document.write( "\"2y+=+-1\"
\n" ); document.write( ".
\n" ); document.write( "Solve for y by dividing both sides by 2 to get:
\n" ); document.write( ".
\n" ); document.write( "\"y+=+%28-1%29%2F2+=+-1%2F2\"
\n" ); document.write( ".
\n" ); document.write( "That's the answer for y.
\n" ); document.write( ".
\n" ); document.write( "Check it out by substituting \"-1%2F2\" for y in the original problem to get ...
\n" ); document.write( ".
\n" ); document.write( "\"log%289%2C%281%2F3%29%29+=+-1%2F2\"
\n" ); document.write( ".
\n" ); document.write( "When you convert this to exponential form you get:
\n" ); document.write( ".
\n" ); document.write( "\"9%5E%28-1%2F2%29+=+1%2F3\"
\n" ); document.write( ".
\n" ); document.write( "But a negative exponent becomes a positive exponent if you put it (along with its base) into
\n" ); document.write( "the denominator of a fraction. So \"9%5E%28-1%2F2%29\" becomes \"1%2F%289%5E%281%2F2%29%29\" and the
\n" ); document.write( "equation is then:
\n" ); document.write( ".
\n" ); document.write( "\"1%2F9%5E%281%2F2%29+=+1%2F3\"
\n" ); document.write( ".
\n" ); document.write( "Then recognize that the exponent \"1%2F2\" tells you to take the square root of its base. So
\n" ); document.write( "\"9%5E%281%2F2%29\" means to take the square root of 9 and the square root of 9 is 3.
\n" ); document.write( "So you can
\n" ); document.write( "replace \"9%5E%281%2F2%29\" by 3 and the equation is finally reduced to:
\n" ); document.write( ".
\n" ); document.write( "\"+1%2F3+=+1%2F3\"
\n" ); document.write( ".
\n" ); document.write( "Since this is true, you know that \"y+=+-1%2F2\" is the correct answer.
\n" ); document.write( ".
\n" ); document.write( "Hope this helps you to understand the problem and how it can be worked.
\n" ); document.write( "
\n" );