document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1065971>Question 1065971</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The longest side of a right triangle is 3 ft longer than three times the length of the shortest side. The other side of the triangle is 3 ft shorter than three times the length of the shortest side.\r<BR>\n" );
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document.write( " Find the lengths of the shortest, longest and the other side of the triangle. \r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #681158 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=681158\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> short side is x<BR>\n" );
document.write( "longest side, the hypotenuse, is 3x+3<BR>\n" );
document.write( "the other side is 3x-3<BR>\n" );
document.write( "Therefore, x^2+(3x-3)^2=(3x+3)^2.<BR>\n" );
document.write( "x^2+9x^2-18x+9=9x^2+18x+9<BR>\n" );
document.write( "x^2-36x=0<BR>\n" );
document.write( "x(x-36)=0<BR>\n" );
document.write( "x=36 ft, the shortest side<BR>\n" );
document.write( "the other side is 105 ft.<BR>\n" );
document.write( "the hypotenuse is 111 ft.<BR>\n" );
document.write( "divisible by 3, it is a 12-35-37 triangle<BR>\n" );
document.write( "12^2=144<BR>\n" );
document.write( "35^2=1225<BR>\n" );
document.write( "37^2=1369, which is the sum of the first two. </SPAN>\n" );
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