document.write( "Question 1065962: What is the answer for question 133479? \n" ); document.write( "
Algebra.Com's Answer #681141 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
i believe your answer can be found here:\r
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\n" ); document.write( "\n" ); document.write( "https://www.algebra.com/algebra/homework/Probability-and-statistics/Probability-and-statistics.faq.question.133479.html\r
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\n" ); document.write( "\n" ); document.write( "based on this, the solution would be p(x=3) = .193536 and p(x>4) = p(x=5) + p(x=6) + p(x=7) = .4199...\r
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\n" ); document.write( "\n" ); document.write( "the formula to use is p(x) = c(n,x) * p^x * q^(n-x)\r
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\n" ); document.write( "\n" ); document.write( "x is the number of occurrences you are looking for.
\n" ); document.write( "p is the probability of success.
\n" ); document.write( "q is the probability of failure which is equal to 1 - p(x).\r
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\n" ); document.write( "\n" ); document.write( "c(n,x) is the number of possible ways you can get x things fr0om n things when order is not important.\r
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\n" ); document.write( "\n" ); document.write( "you have:\r
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\n" ); document.write( "\n" ); document.write( "n = 7
\n" ); document.write( "p = .6
\n" ); document.write( "q = .4\r
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\n" ); document.write( "\n" ); document.write( "for example:\r
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\n" ); document.write( "\n" ); document.write( "p(x=3) is equal to c(7,3) * .6^3 * .4^4\r
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\n" ); document.write( "\n" ); document.write( "c(7,3) = 35\r
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\n" ); document.write( "\n" ); document.write( "formula becomes p(x=3) = 35 * .6^3 * .4^4\r
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\n" ); document.write( "\n" ); document.write( "solve for p(x=3) to get p(x=3) = .193536\r
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\n" ); document.write( "\n" ); document.write( "the formula for c(n,x) is n! / (x! * (n-x)!)\r
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\n" ); document.write( "\n" ); document.write( "when n = 7 and x = 3, this formula becomes c(7,3) = 7! / (3! * 4!).
\n" ); document.write( "this becomes c(7,3) = (7*6*5*4*3*2*1) / (3*2*1*4*3*2*1).
\n" ); document.write( "factor out 4*3*2*1 and this becomes c(7,3) = (7*6*5)/(3*2*1)
\n" ); document.write( "solve to get c(7,3) = 7*5 = 35\r
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\n" ); document.write( "\n" ); document.write( "you can do the same for p(5) and p(6) and p(7) and you will get p(x>4) is equal to the sum of those probabilities.\r
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