document.write( "Question 1065866: The length of a rectangular swimming pool is twice the size of the Width decreased by fifty. Find the dimensions of the pool if its perimeter is 320 yards.
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Algebra.Com's Answer #681048 by josmiceli(19441) $\"\"$ $\"About$

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$\"+L+=+2W+-+50+\"$
\n" ); document.write( " $\"+P+=+320+\"$
\n" ); document.write( "The formula for perimeter is:
\n" ); document.write( " $\"+P+=+2L+%2B+2W+\"$
\n" ); document.write( " $\"+320+=+2%2A%28+2W+-+50+%29+%2B+2W+\"$
\n" ); document.write( " $\"+320+=+4W+-+100+%2B+2W+\"$
\n" ); document.write( " $\"+6W+=+420+\"$
\n" ); document.write( " $\"+W+=+70+\"$
\n" ); document.write( "and
\n" ); document.write( " $\"+L+=+2%2A70+-+50+\"$
\n" ); document.write( " $\"+L+=+140+-+50+\"$
\n" ); document.write( " $\"+L+=+90+\"$
\n" ); document.write( "The pool is 70 yds x 90 yds
\n" ); document.write( "----------------------------
\n" ); document.write( "check:
\n" ); document.write( " $\"+P+=+2L+%2B+2W+\"$
\n" ); document.write( " $\"+P+=+2%2A90+%2B+2%2A70+\"$
\n" ); document.write( " $\"+P+=+180+%2B+140+\"$
\n" ); document.write( " $\"+P+=+320+\"$ yds
\n" ); document.write( "OK
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