document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1065863>Question 1065863</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the point M that is two seventh of the distance from A(-9,2) to B(-2,-12)\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #681042 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=681042\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Take 2/7 of the x distance, which is 7, so the x-value is 2 away from -9 towards -2 or -7.<BR>\n" );
document.write( "The y is 2/7 of the y distance, which is 14 from 2 to -12, or -2.<BR>\n" );
document.write( "(-7,-2)<BR>\n" );
document.write( "Distance is the sqrt { (x2-x1)^2+ (y2-y1)^2}= sqrt (49+196)=sqrt (245=sqrt(49)*sqrt(5)=7 sqrt (5)<BR>\n" );
document.write( "distance from point A to (-7,-2) is sqrt (4+16)=sqrt (20)=2 sqrt (5), which is 2/7 the distance to 7 sqrt (5). </SPAN>\n" );
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