document.write( "Question 93381: been researching this problem and i believe it is an inconsistent equation
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document.write( "after I have factored all the denominators and try to multiply through to get rid of the fractions and continue working the problem get stuck.All the other problems I have done before have the same combinations once factored not the case here.\r
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document.write( "4/(x^2+3x-10)-1/(x^2+x-6)=3/(x^2-x-12) \n" );
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Algebra.Com's Answer #68104 by bucky(2189)![]() ![]() ![]() You can put this solution on YOUR website! From your answer I gathered that you understand the methods that need to be applied to solve \n" ); document.write( "the problem, but you are probably making a minor math mistake somewhere that is leading you astray. \n" ); document.write( ". \n" ); document.write( "There is a solution for x and here's how you go about getting it. \n" ); document.write( ". \n" ); document.write( "Start with the given problem: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Factor each of the three denominators. When you do you get: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Then identify each of the individual factors. The list is: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "When you multiply these together, you get a common denominator that can be used for each \n" ); document.write( "term. As an abbreviation, use CD for this common denominator. \n" ); document.write( ". \n" ); document.write( "To put a term over this common denominator, you must multiply its numerator by those factors \n" ); document.write( "in the common denominator that were not in its original denominator. Putting the terms over \n" ); document.write( "the common denominator results in: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Now you can get rid of the CD by multiplying both sides of this equation (all terms) by \n" ); document.write( "the CD. When you do that the CD multiplier cancels with the CD in the denominator \n" ); document.write( "and you are left with just the numerators of the terms in the problem. That is, you are \n" ); document.write( "left with: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "In each of the three groupings, multiply the two sets of parentheses to get: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Now multiply by the constants in front of the parentheses (note that in the second term \n" ); document.write( "on the left side the constant is -1). When you do those multiplications you get: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Combine the like terms on each side of the equation. On the left side you have \n" ); document.write( " \n" ); document.write( "to -5x. And finally you have \n" ); document.write( "So the left \n" ); document.write( "side is reduced to \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "If you subtract \n" ); document.write( "side are eliminated and you are left with: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Subtract 9x from both sides and the equation becomes: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Add +28 to both sides and you get: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Finally solve for x by dividing both sides by -14 and you have: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "And that's the answer ... \n" ); document.write( ". \n" ); document.write( "Hope this helps you to find your math error. \n" ); document.write( " \n" ); document.write( " |