document.write( "Question 93381: been researching this problem and i believe it is an inconsistent equation
\n" ); document.write( "after I have factored all the denominators and try to multiply through to get rid of the fractions and continue working the problem get stuck.All the other problems I have done before have the same combinations once factored not the case here.\r
\n" ); document.write( "\n" ); document.write( "4/(x^2+3x-10)-1/(x^2+x-6)=3/(x^2-x-12)
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Algebra.Com's Answer #68104 by bucky(2189)\"\" \"About 
You can put this solution on YOUR website!
From your answer I gathered that you understand the methods that need to be applied to solve
\n" ); document.write( "the problem, but you are probably making a minor math mistake somewhere that is leading you astray.
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\n" ); document.write( "There is a solution for x and here's how you go about getting it.
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\n" ); document.write( "Start with the given problem:
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\n" ); document.write( "\"4%2F%28x%5E2%2B3x-10%29+-+1%2F%28x%5E2%2Bx-6%29+=+3%2F%28x%5E2-x-12%29\"
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\n" ); document.write( "Factor each of the three denominators. When you do you get:
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\n" ); document.write( "Then identify each of the individual factors. The list is:
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\n" ); document.write( "\"x-2\"
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\n" ); document.write( "When you multiply these together, you get a common denominator that can be used for each
\n" ); document.write( "term. As an abbreviation, use CD for this common denominator.
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\n" ); document.write( "To put a term over this common denominator, you must multiply its numerator by those factors
\n" ); document.write( "in the common denominator that were not in its original denominator. Putting the terms over
\n" ); document.write( "the common denominator results in:
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\n" ); document.write( "Now you can get rid of the CD by multiplying both sides of this equation (all terms) by
\n" ); document.write( "the CD. When you do that the CD multiplier cancels with the CD in the denominator
\n" ); document.write( "and you are left with just the numerators of the terms in the problem. That is, you are
\n" ); document.write( "left with:
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\n" ); document.write( "\"4%28x%2B3%29%28x-4%29+-+%28x%2B5%29%28x-4%29+=+3%28x-2%29%28x%2B5%29\"
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\n" ); document.write( "In each of the three groupings, multiply the two sets of parentheses to get:
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\n" ); document.write( "\"4%28x%5E2+-x+-12%29-+%28x%5E2%2Bx-20%29=+3%28x%5E2%2B3x-10%29\"
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\n" ); document.write( "Now multiply by the constants in front of the parentheses (note that in the second term
\n" ); document.write( "on the left side the constant is -1). When you do those multiplications you get:
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\n" ); document.write( "\"4x%5E2+-4x+-48+-x%5E2+-+x+%2B20+=+3x%5E2+%2B9x+-30\"
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\n" ); document.write( "Combine the like terms on each side of the equation. On the left side you have \"4x%5E2\" and
\n" ); document.write( "\"-x%5E2\" which combine to \"3x%5E2\". You also have \"-4x\" and \"-x\" which combine
\n" ); document.write( "to -5x. And finally you have \"-48\" and \"20\" which combine to \"-28\".
\n" ); document.write( "So the left
\n" ); document.write( "side is reduced to \"3x%5E2-5x-28\" and the equation becomes:
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\n" ); document.write( "\"3x%5E2+-5x-28+=+3x%5E2+%2B+9x+-+30\"
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\n" ); document.write( "If you subtract \"3x%5E2\" from both sides, the \"3x%5E2\" terms on the left and the right
\n" ); document.write( "side are eliminated and you are left with:
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\n" ); document.write( "\"-5x-28+=+9x-30\"
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\n" ); document.write( "Subtract 9x from both sides and the equation becomes:
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\n" ); document.write( "\"-14x-28+=+-30\"
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\n" ); document.write( "Add +28 to both sides and you get:
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\n" ); document.write( "\"-14x+=+-2\"
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\n" ); document.write( "Finally solve for x by dividing both sides by -14 and you have:
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\n" ); document.write( "\"x+=+%28-2%29%2F%28-14%29+=+1%2F7\"
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\n" ); document.write( "And that's the answer ... \"x+=+1%2F7\"
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\n" ); document.write( "Hope this helps you to find your math error.
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