document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1065648>Question 1065648</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If 2 times a number is decreased by 6&#8203;, the principal square root of this difference is 7&#8195;&#8195;less than the number. Find the&#8203; number(s). </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #681024 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=681024\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> number is x<BR>\n" );
document.write( "2x-6 is the number whose square root is x-7<BR>\n" );
document.write( "square both sides<BR>\n" );
document.write( "2x-6=(x-7)^2=x^2-14x+49<BR>\n" );
document.write( "0=x^2-16x+55<BR>\n" );
document.write( "0=(x-11)(x-5)<BR>\n" );
document.write( "x=11 or 5<BR>\n" );
document.write( "if 11, square root of 16 is 4, 7 fewer than 11.<BR>\n" );
document.write( "if 5, square root of 4 is 2, and that is not 7 fewer than 5, and that is the principal square root.<BR>\n" );
document.write( "11 is the number. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );