document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1065836>Question 1065836</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A butcher makes a blend of stew meat from beef that sells for $2.80 a pound and pork that sells for $3.25 a pound. How many pounds of each meat should be used to get 30 pounds of a mix that can be sold for $3.10 a pound? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #681005 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=681005\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> total amount: 30<BR>\n" );
document.write( "amount of beef at 2.80: x<BR>\n" );
document.write( "amount of pork at 3.25: 30-x<BR>\n" );
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document.write( "2.80x+3.25(30-x) = 3.10(30)<BR>\n" );
document.write( "2.80x-3.25x+97.50 = 93<BR>\n" );
document.write( "-0.45x = -4.50 divide both sides by -0.45 and remember -/- = +<BR>\n" );
document.write( "x = 10 he needs 10lb of beef and 30-10 = 20lb of pork </SPAN>\n" );
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