document.write( "Question 1065825: Joe deposits $1,300 in an account that pays 2% annual interest compounded continuously. \r
\n" ); document.write( "\n" ); document.write( "a. How much will Joe have in his account after 5 years?
\n" ); document.write( "b. How long will it take Joe to double his money? Use natural logarithms and explain your answer.
\n" ); document.write( "c. In one or two sentences explain how the answers in part a and b will chance if the interest is compounded annually? You do not need to show . . . calculations to answer this part.
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Algebra.Com's Answer #681002 by addingup(3677)\"\" \"About 
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a):
\n" ); document.write( "P*e^(rt)
\n" ); document.write( "1300*e^(rt)
\n" ); document.write( "1300*e^(0.02*5) = 1436.72
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\n" ); document.write( "b):
\n" ); document.write( "(ln(2))/0.02 = 34.66
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\n" ); document.write( "c)
\n" ); document.write( "you answer it. The formula for a) compounded annually is: Amount = 1300(1+0.02)^5
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