document.write( "Question 1065750: A snack company increases the side length of a square cracker by 2 centimeters. The new cracker has an area of 28 square centimeters larger than the old version. What was the area of the old cracker?\r
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Algebra.Com's Answer #680920 by josgarithmetic(39631)\"\" \"About 
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Old cracker side length, x\r
\n" ); document.write( "\n" ); document.write( "New cracker side length, x+2\r
\n" ); document.write( "\n" ); document.write( "New cracker has a larger area than before.
\n" ); document.write( "The difference is 28 square centimeters.
\n" ); document.write( "\"%28x%2B2%29%5E2-x%5E2=28\"\r
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\n" ); document.write( "\n" ); document.write( "Solve for x and evaluate x^2.\r
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\n" ); document.write( "\n" ); document.write( "-
\n" ); document.write( "\"x=6\"
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\n" ); document.write( "\"x%5E2=36\"
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