document.write( "Question 1065707: The area of a rectangle is 135 in.² the ratio of the links to the width is 5 to 3 find the length and the width \n" ); document.write( "
Algebra.Com's Answer #680905 by ikleyn(52781)\"\" \"About 
You can put this solution on YOUR website!
.
\n" ); document.write( "The area of a rectangle is 135 in.² the ratio of the \"highlight%28cross%28links%29%29\" length to the width is 5 to 3 find the length and the width
\n" ); document.write( "~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\r\n" );
document.write( "The condition says that \"L%2FW\" = \"5%2F3\".\r\n" );
document.write( "\r\n" );
document.write( "It means that L = \"%285%2F3%29%2AW\".     (*)\r\n" );
document.write( "\r\n" );
document.write( "The condition  also says that \r\n" );
document.write( "\r\n" );
document.write( "LW = 135.\r\n" );
document.write( "\r\n" );
document.write( "Substitute (*) to there. You will get\r\n" );
document.write( "\r\n" );
document.write( "\"%285%2F3%29%2AW%5E2\" = 135  --->  \"5W%5E2\" = 135*3  --->>> \"W%5E2\" = \"%28135%2A3%29%2F5\" = 27*3 = 81.\r\n" );
document.write( "\r\n" );
document.write( "Hence, W = \"sqrt%2881%29\" = 9.\r\n" );
document.write( "\r\n" );
document.write( "Then L = \"%285%2F3%29%2A9\" = 15.\r\n" );
document.write( "\r\n" );
document.write( "Answer. The length is 15 inches.  The width is 9 inches.\r\n" );
document.write( "
\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );