document.write( "Question 93476This question is from textbook precalculus with limits
\n" ); document.write( ": how do you find two points on a line with only one point and the slope?
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Algebra.Com's Answer #68084 by checkley75(3666)\"\" \"About 
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GIVEN 1 POINT OF (2,-3) & A SLOPE (m) OF 3.
\n" ); document.write( "YOU SOLVE THE STANDARD LINE EQUATION :
\n" ); document.write( "Y=mX+b WHERE (m)=SLOPE & (b)=Y INTERCEPT.
\n" ); document.write( "SUBSTITUTE THE [POINTS COORDINATES FOR X&Y & THE 3 FOR THE SLOPE & SOLVE FOR THE Y INTERCEPT (b)
\n" ); document.write( "-3=3*2+b
\n" ); document.write( "-3=6+b
\n" ); document.write( "b=-3-6
\n" ); document.write( "b=-9 SO THE LINE EQUATION IS
\n" ); document.write( "Y=3X-9 FOR A SLOPE OF 3 THROUGH THE POINT (2,-3)
\n" ); document.write( "NOW THAT YOU HAVE THE EQUATION SET X=0 & SOLE FOR Y:
\n" ); document.write( "Y=3*0-9
\n" ); document.write( "Y=-9 OR THE POINT (0,-9) IS ANOTHER POINT OIN THIS LINE.
\n" ); document.write( "SET Y=0 & SOLVE FOR X
\n" ); document.write( "0=3X-9
\n" ); document.write( "3X=9
\n" ); document.write( "X=3 OR (3,0) IS ANOTHER POINT.
\n" ); document.write( "GRAPH FOLLOWS:
\n" ); document.write( "\"+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+y+=+3x+-9%29+\" (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, y = 3x -9). \n" ); document.write( "
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