document.write( "Question 1065665: Three consecutive integers are such that the first integer plus twice the second integer plus five less than the third integer is 27. What are the integers? \n" ); document.write( "
Algebra.Com's Answer #680838 by addingup(3677)![]() ![]() You can put this solution on YOUR website! x+2(x+1)+x+2-5 = 27 \n" ); document.write( "x+2x+2+x-3 = 27 \n" ); document.write( "group like terms (it doesn't change the result, but it's better/easier) \n" ); document.write( "2x+x+x+2-3 = 27 \n" ); document.write( "4x-1 = 27 \n" ); document.write( "4x = 28 \n" ); document.write( "x = 7 \n" ); document.write( "------------------------------- \n" ); document.write( "Check: \n" ); document.write( "7+2(8)+(9-5) = 27 \n" ); document.write( "7+16+4 = 27 Correct. \n" ); document.write( ": \n" ); document.write( "John \n" ); document.write( " |