document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1065664>Question 1065664</A>: <I><SPAN STYLE=\"word-break: break-all;\"> this conical glass holds 150ml. its top radius is 4 cm find its depth </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #680836 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=680836\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> convert 150ml to cubic cm<BR>\n" );
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document.write( "1 ml is 1 cubic cm, therefore 150 ml = 150 cubic cm<BR>\n" );
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document.write( "150 = 1/3 × pi × r^2 × h<BR>\n" );
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document.write( "Note conical means cone shaped<BR>\n" );
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document.write( "150 = (1/3) * (22/7) * 4^2 * d, where d is depth<BR>\n" );
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document.write( "150 = 352d / 21<BR>\n" );
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document.write( "352d = 150 * 21<BR>\n" );
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document.write( "d = 8.94886 approx 8.9<BR>\n" );
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document.write( "depth of glass is approximately 8.9 cm<BR>\n" );
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