document.write( "Question 1065659: Please help me with this problem. The Width of a rectangle is 3 feet shorter than its length. The perimeter is 306 feet. Let x equal the length of the rectangle. The formula is p= 2L+2w. What is the length and the width of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #680834 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! w = x - 3 \n" ); document.write( ": \n" ); document.write( "306 = 2x + 2(x - 3) \n" ); document.write( ": \n" ); document.write( "306 = 2x + 2x - 6 \n" ); document.write( ": \n" ); document.write( "4x = 312 \n" ); document.write( ": \n" ); document.write( "x = 78 \n" ); document.write( ": \n" ); document.write( "****************************** \n" ); document.write( "length of rectangle = 78 feet \n" ); document.write( "width of rectangle = 75 feet \n" ); document.write( ": \n" ); document.write( "check our answer \n" ); document.write( ": \n" ); document.write( "306 = 2 * 78 + 2 * 75 \n" ); document.write( ": \n" ); document.write( "306 = 156 + 150 \n" ); document.write( ": \n" ); document.write( "306 = 306 \n" ); document.write( ": \n" ); document.write( "our answer checks \n" ); document.write( "****************************** \n" ); document.write( " |