document.write( "Question 1065533: The coffee Jim likes is composed of 98.5% water and 1.5% cocoa. The coffee John likes is composed of 97% water and 3% cocoa.\r
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document.write( "How many ounces of water, x, should be added to 20 ounces of coffee that John likes to make the coffee that Jim likes?\r
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document.write( "x = ___ ounces \n" );
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Algebra.Com's Answer #680819 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! The coffee Jim likes is composed of 98.5% water and 1.5% cocoa. \n" ); document.write( " The coffee John likes is composed of 97% water and 3% cocoa. \n" ); document.write( "How many ounces of water, x, should be added to 20 ounces of coffee that John likes to make the coffee that Jim likes? \n" ); document.write( ": \n" ); document.write( "write an equation in terms of percent cocoa \n" ); document.write( ".03(20) = .015(x+20) \n" ); document.write( ".6 = .015x + .3 \n" ); document.write( ".6 - .3 = .015x \n" ); document.write( ".3 = .015x \n" ); document.write( "x = .3/.015 \n" ); document.write( "x = 20 oz of water added \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "The original AMT of cocoa is unchanged \n" ); document.write( ".03(20) = .6 oz is the original amt of cocoa \n" ); document.write( "Check the percent \n" ); document.write( ".6/20 = .03 Johns \n" ); document.write( ".6/40 = .015 Jims \n" ); document.write( " \n" ); document.write( " |