document.write( "Question 1065588: For which of the following operations will the complex numbers (4-3i) and (1+2i) produce a real solution? Find the solution.\r
\n" ); document.write( "\n" ); document.write( "A) Addition
\n" ); document.write( "B) Subtraction
\n" ); document.write( "C) Multiplication
\n" ); document.write( "D) Division\r
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\n" ); document.write( "\n" ); document.write( "Thanks!
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Algebra.Com's Answer #680779 by josgarithmetic(39621)\"\" \"About 
You can put this solution on YOUR website!
If you are not sure, try each of them and see.\r
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\n" ); document.write( "\n" ); document.write( "Addition will give you an imaginary component, and so will subtraction.\r
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\n" ); document.write( "\n" ); document.write( "Multiplication?
\n" ); document.write( "\"4-3i%2B2i-6i%5E2\"
\n" ); document.write( "No. You have the imaginary, \"-i\" as part of the number.\r
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\n" ); document.write( "\n" ); document.write( "Division?
\n" ); document.write( "-
\n" ); document.write( "\"%284-3i%29%2F%281%2B2i%29\"\r
\n" ); document.write( "\n" ); document.write( "\"%28%284-3i%29%2F%281%2B2i%29%29%28%281-2i%29%2F%281-2i%29%29\", simply multiplication by 1\r
\n" ); document.write( "\n" ); document.write( "\"%284-3i-8i%2B6i%5E2%29%2F%281-4i%5E2%29\"------but you still will have an imaginary component in the numerator.
\n" ); document.write( "-
\n" ); document.write( "You can also try the reciprocal and see what it will be, but...
\n" ); document.write( "You try it.
\n" ); document.write( "Unless this gives you a fully REAL result, none of the choices will produce a real solution.
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