document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1065572>Question 1065572</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Mariana Coanda wishes to blend candy selling for $1.20 per lb. with candy selling for $1.80 per lb. to get a mixture that will be sold for $1.40 per lb. How many pounds of the $1.20 and the $1.80 candies should be used to get 45 lbs. of the mixture? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #680752 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=680752\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1.20x+1.80(45-x) = 1.40(45)<BR>\n" );
document.write( "1.20x+81-1.80x = 63<BR>\n" );
document.write( "1.20x-1.80x = 63-81<BR>\n" );
document.write( "-0.60x = -18 divide both sides by 0.60, and remember -/- = +<BR>\n" );
document.write( "x = 30<BR>\n" );
document.write( "She needs 30 pounds of the 1.20 candy and 45-30 = 15 pounds of the 1.80 </SPAN>\n" );
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