document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=93490>Question 93490</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of the yard is 130 feet. If the length is 10 less than 2 times the width, what are the dimensions? Show all work.\r<BR>\n" );
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document.write( "Thanks alot ! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #68073 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=68073\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L=2W-10 IS THE LENGTH<BR>\n" );
document.write( "W=WIDTH<BR>\n" );
document.write( "2W+2(2W-10)=130<BR>\n" );
document.write( "2W+4W-20=130<BR>\n" );
document.write( "6W=130+20<BR>\n" );
document.write( "6W=150<BR>\n" );
document.write( "W=150/6<BR>\n" );
document.write( "W=25 IS THE WIDTH.<BR>\n" );
document.write( "2*25-10=50-10=40 IS THE LENGTH.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "2*25+2*40=130<BR>\n" );
document.write( "50+80=130<BR>\n" );
document.write( "130=130 </SPAN>\n" );
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