Algebra.Com's Answer #680690 by ikleyn(52790)![\"\"](\"/images/stars/stars-13.gif\")  
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document.write( "two candles of equal length are lit at the same time. one candle takes 6 hours to burn out and the other takes 3 hours.
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document.write( "After how much time will the slower burning candle be exactly twice as long as the faster burning one?
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document.write( "Faster candle rate of burning is  of its length per hour.\r\n" );
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document.write( "Slower candle rate of burning is  of its length per hour.\r\n" );
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document.write( "The length of the remaining part for the faster candle is  after t hours.\r\n" );
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document.write( "The length of the remaining part for the slower candle is  after t hours.\r\n" );
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document.write( "The question asks about time t when Slower(t) = 2*Faster(t), or\r\n" );
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document.write( " =  .\r\n" );
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document.write( "To solve for t, multiply both sides by  . You will get\r\n" );
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document.write( " =  , or\r\n" );
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document.write( "12 - 4t = 6 - t ---> 12 - 6 = 4t - t ---> 6 = 3t ---> t = 2.\r\n" );
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document.write( "Answer. After 2 hours.\r\n" );
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document.write( "If you have questions or want to say \"thanks\", then please mention the ID number of this problem (# 1065529) in your response.\r
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