document.write( "Question 1065487: A takes 30 minutes to reach a shop from his residence. B takes 20 minutes to reach the same shop from same residence. one day A departed to shop at 8a.m. if B departed 5 minutes later. at what time B passes A?
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Algebra.Com's Answer #680634 by ikleyn(52800)\"\" \"About 
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\n" ); document.write( "A takes 30 minutes to reach a shop from his residence. B takes 20 minutes to reach the same shop from same residence.
\n" ); document.write( "one day A departed to shop at 8a.m. if B departed 5 minutes later. at what time B passes A?
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document.write( "Let D be the distance from the residence to the shop.\r\n" );
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document.write( "A has the speed \"D%2F30\" units per minute, while B has the speed \"D%2F20\" units per minute.\r\n" );
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document.write( "Let \"t\" be the time counted from 8:05 am.\r\n" );
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document.write( "The distance for B is \"t%2A%28D%2F20%29\".\r\n" );
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document.write( "The distance for A is \"5%2A%28D%2F30%29+%2B+t%2A%28D%2F30%29\".\r\n" );
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document.write( "The equation for the time is\r\n" );
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document.write( "\"t%2A%28D%2F20%29\" = \"5%2A%28D%2F30%29+%2B+t%2A%28D%2F30%29\".\r\n" );
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document.write( "Multiply everything by 60/D. You will get\r\n" );
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document.write( "3t = 5*2 + 2t,   or\r\n" );
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document.write( "3t - 2t = 10,\r\n" );
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document.write( "t = 10. \r\n" );
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document.write( "Answer.  B passes A at 8:15 am.\r\n" );
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