document.write( "Question 1065407: Ben starts walking along a path at 2 mi/h. One and a half hours after Ben leaves, his sister Amanda begins jogging along the same path at 4 mi/h. How long will it be before Amanda catches up to Ben ? \n" ); document.write( "
Algebra.Com's Answer #680602 by josgarithmetic(39618)\"\" \"About 
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document.write( "                SPEED      TIME       DISTANCE\r\n" );
document.write( "BEN              2         t+1.5        d\r\n" );
document.write( "AMANDA           4          t           d\r\n" );
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\n" ); document.write( "\n" ); document.write( "RT=D, constant travel rates rule for rate R, time T, distance D.\r
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\n" ); document.write( "\n" ); document.write( "\"system%282%28t%2B1.5%29=d%2C4t=d%29\"\r
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\n" ); document.write( "\n" ); document.write( "Distance for each is the same d.\r
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\n" ); document.write( "\n" ); document.write( "\"2%28t%2B1.5%29=4t\"\r
\n" ); document.write( "\n" ); document.write( "\"t%2B1.5=2t\"\r
\n" ); document.write( "\n" ); document.write( "\"t=1.5\"------------- One and a half hours for Amanda to catch-up to Ben.
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