document.write( "Question 93472This question is from textbook
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document.write( ": Find the what what and the what? please help me!!! Find (a)the directrix,
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document.write( "(b) the focus and (c) the roots of the parabola y = x^2 - 5x + 4
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document.write( "(a)_________________
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document.write( "(b)_________________
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document.write( "(c)_________________ \n" );
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Algebra.Com's Answer #68059 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Find (a)the directrix, \n" ); document.write( "(b) the focus and (c) the roots of the parabola y = x^2 - 5x + 4 \n" ); document.write( "---------------------- \n" ); document.write( "Complete the square on the x terms and keep the equation balanced: \n" ); document.write( " x^2 - 5x + 4 = y \n" ); document.write( "x^2 -5x + ? = y-4 + ? \n" ); document.write( "x^2 + 5x + (5/2)^2 = y - 16/4 + (25/4) \n" ); document.write( "Factor and simplify to get: \n" ); document.write( "(x+(5/2))^2 = (y+9/4) \n" ); document.write( "Note: This follows the form (x-h)^2 = 4P(y-k)\r \n" ); document.write( "\n" ); document.write( "-------------------------------- \n" ); document.write( "a) directrix is x = -5/2 \n" ); document.write( "------------------ \n" ); document.write( "b) 4P=1; p=1/4 \n" ); document.write( "Vertex is (-5/2 , -9/4) \n" ); document.write( "Focus is (-5/2 , -9/4 + 1/4) = (-5/2 , -2) \n" ); document.write( "--------------------- \n" ); document.write( "c) Roots: \n" ); document.write( "y = x^2 - 5x + 4 \n" ); document.write( "Let y=0 and solve for x: \n" ); document.write( "x^2-5x+4 = 0 \n" ); document.write( "(x-4)(x-1) = 0 \n" ); document.write( "x=4 or x=1 \n" ); document.write( "========================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |