document.write( "Question 1065360: A towns old street sweeper can clean the streets in 60 hrs. Working together with a new sweeper they can do the job in 15 hrs. How long would it take the new sweeper to do the job working alone? \n" ); document.write( "
Algebra.Com's Answer #680507 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! Old sweeper's rate: \n" ); document.write( "[ 1 job ] / [ 60 hrs ] \n" ); document.write( "New sweeper's rate: \n" ); document.write( "[ 1 job ] / [ t hrs ] \n" ); document.write( "Their rate working together: \n" ); document.write( "[ 1 job ] / [ 15 hrs ] \n" ); document.write( "--------------------------- \n" ); document.write( "Add their rates of working to get \n" ); document.write( "their rate working together \n" ); document.write( " \n" ); document.write( "Multiply both sides by \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "------------- \n" ); document.write( "The new sweeper does the job in 20 hrs \n" ); document.write( "working alone \n" ); document.write( "-------------------- \n" ); document.write( "check: \n" ); document.write( " \n" ); document.write( "Multiply both sides by \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "OK \n" ); document.write( " |