document.write( "Question 1065360: A towns old street sweeper can clean the streets in 60 hrs. Working together with a new sweeper they can do the job in 15 hrs. How long would it take the new sweeper to do the job working alone? \n" ); document.write( "
Algebra.Com's Answer #680507 by josmiceli(19441)\"\" \"About 
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Old sweeper's rate:
\n" ); document.write( "[ 1 job ] / [ 60 hrs ]
\n" ); document.write( "New sweeper's rate:
\n" ); document.write( "[ 1 job ] / [ t hrs ]
\n" ); document.write( "Their rate working together:
\n" ); document.write( "[ 1 job ] / [ 15 hrs ]
\n" ); document.write( "---------------------------
\n" ); document.write( "Add their rates of working to get
\n" ); document.write( "their rate working together
\n" ); document.write( "\"+1%2F60+%2B+1%2Ft+=+1%2F15+\"
\n" ); document.write( "Multiply both sides by \"+60t+\"
\n" ); document.write( "\"+t+%2B+60+=+4t+\"
\n" ); document.write( "\"+3t+=+60+\"
\n" ); document.write( "\"+t+=+20+\"
\n" ); document.write( "-------------
\n" ); document.write( "The new sweeper does the job in 20 hrs
\n" ); document.write( "working alone
\n" ); document.write( "--------------------
\n" ); document.write( "check:
\n" ); document.write( "\"+1%2F60+%2B+1%2F20+=+1%2F15+\"
\n" ); document.write( "Multiply both sides by \"+60+\"
\n" ); document.write( "\"+1+%2B+3+=+4+\"
\n" ); document.write( "\"+4+=+4+\"
\n" ); document.write( "OK
\n" ); document.write( "
\n" );