document.write( "Question 1065330: The perimeter of a rectangle is 42cm. if the diagonal is 15cm find the width of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #680491 by math_helper(2461)![]() ![]() You can put this solution on YOUR website! l,w = length, width, respectively \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(1) —> \n" ); document.write( "\n" ); document.write( "Square both sides of (2): \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now substitute \"21-w\" for \"l\" in this last expression: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Combine like terms, and rearrange: \n" ); document.write( " \n" ); document.write( "Divide through by 2: \n" ); document.write( " \n" ); document.write( "Factor: \n" ); document.write( " \n" ); document.write( " w = 9 or w = 12\r \n" ); document.write( "\n" ); document.write( "If w = 9, (1) tells us l = 12 \n" ); document.write( "if w = 12, (1) tells us l = 9 (<<< discard because convention is l>w for a rectangle)\r \n" ); document.write( "\n" ); document.write( "— \n" ); document.write( "Ans: \n" ); document.write( " \n" ); document.write( "— \n" ); document.write( "Check: \n" ); document.write( " Diagonal = \n" ); document.write( " Perimeter = |