document.write( "Question 1065336: Jane is now twice as old as Joy. In four years, she will be ten years older than Joy. Find their present ages.
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Algebra.Com's Answer #680489 by math_helper(2461)\"\" \"About 
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\n" ); document.write( " J = Jane's age
\n" ); document.write( " K = Joy's age
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\n" ); document.write( " J = 2K (1)
\n" ); document.write( " J+4 = (K+4)+10 (2)
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\n" ); document.write( "Substitute 2K for J (from (1)) into (2):
\n" ); document.write( " 2K+4 = K+4+10
\n" ); document.write( " K = 10 —> from (1): J = 2K = 20
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\n" ); document.write( "Ans:
\n" ); document.write( " Joy is 10, Jane is 20
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\n" ); document.write( "Check:
\n" ); document.write( " Joy's age in 4 years: 10+4 = 14
\n" ); document.write( " Jane's age in 4 years: 20+4 = 24 = 14+10 (ok, 10 more than Joy's)
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