document.write( "Question 1065336: Jane is now twice as old as Joy. In four years, she will be ten years older than Joy. Find their present ages.
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Algebra.Com's Answer #680489 by math_helper(2461)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " J = Jane's age \n" ); document.write( " K = Joy's age \n" ); document.write( "--- \n" ); document.write( " J = 2K (1) \n" ); document.write( " J+4 = (K+4)+10 (2) \n" ); document.write( "--- \n" ); document.write( "Substitute 2K for J (from (1)) into (2): \n" ); document.write( " 2K+4 = K+4+10 \n" ); document.write( " K = 10 —> from (1): J = 2K = 20 \n" ); document.write( "— \n" ); document.write( "Ans: \n" ); document.write( " Joy is 10, Jane is 20 \n" ); document.write( "—— \n" ); document.write( "Check: \n" ); document.write( " Joy's age in 4 years: 10+4 = 14 \n" ); document.write( " Jane's age in 4 years: 20+4 = 24 = 14+10 (ok, 10 more than Joy's) \n" ); document.write( " \n" ); document.write( " |