document.write( "Question 1065310: The equation 2x^2-5x=-12 is rewritten in the form of 2(x-p)^2+q=0. What is the value of q? \n" ); document.write( "
Algebra.Com's Answer #680458 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
\"+2%2A%28+x+-+p+%29%5E2+%2B+q+=+0+\"
\n" ); document.write( "\"+2%2A%28+x%5E2+-+2p%2Ax+%2B+p%5E2+%29+%2B+q+=+0+\"
\n" ); document.write( "\"+2x%5E2+-+4p%2Ax+%2B+2p%5E2+%2B+q+=+0+\"
\n" ); document.write( "-----------------------------------
\n" ); document.write( "The given equation is:
\n" ); document.write( "\"+2x%5E2+-+5x+=+-12+\"
\n" ); document.write( "\"+2x%5E2+-+5x+%2B+12+=+0+\"
\n" ); document.write( "------------------------------
\n" ); document.write( "\"+-4p+=+-5+\"
\n" ); document.write( "\"+p+=+%28-5%29%2F%28-4%29+\"
\n" ); document.write( "\"+p+=+5%2F4+\"
\n" ); document.write( "------------------
\n" ); document.write( "\"+2p%5E2+%2B+q+=+12+\"
\n" ); document.write( "\"+2%2A%28+5%2F4+%29%5E2+%2B+q+=+12+\"
\n" ); document.write( "\"+2%2A%28+25%2F16+%29+%2B+q+=+12+\"
\n" ); document.write( "\"+q+=+12+-+50%2F16+\"
\n" ); document.write( "\"+q+=+12+-+25%2F8+\"
\n" ); document.write( "\"+q+=+96%2F8+-+25%2F8+\"
\n" ); document.write( "\"+q+=+71%2F8+\"
\n" ); document.write( "-------------------------
\n" ); document.write( "check:
\n" ); document.write( "\"+2%2A%28+x+-+p+%29%5E2+%2B+q+=+0+\"
\n" ); document.write( "\"+2%2A%28+x+-+5%2F4+%29%5E2+%2B+71%2F8+=+0+\"
\n" ); document.write( "\"+2%2A%28+x%5E2+-+%2810%2F4%29%2Ax+%2B+25%2F16+%29+%2B+71%2F8+=+0+\"
\n" ); document.write( "\"+2x%5E2+-+%2810%2F2%29%2Ax+%2B+25%2F8+%2B+71%2F8+=+0+\"
\n" ); document.write( "\"+2x%5E2+-+5x+%2B+96%2F8+=+0+\"
\n" ); document.write( "\"+2x%5E2+-+5x+%2B+12+=+0+\"
\n" ); document.write( "\"+2x%5E2+-+5x+=+-12+\"
\n" ); document.write( "OK\r
\n" ); document.write( "\n" ); document.write( "
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