document.write( "Question 93461: 2. Suppose that a ball is thrown upward with an initial velocity of 22 ft/sec. If the ball is released at a height of 5 ft., the height equation may be written as h=-16t^2+22t+5 When, to the nearest thousandth of a sec., will the ball be at a height of 9ft. on the way up? \n" ); document.write( "
Algebra.Com's Answer #68043 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "To find the time the ball is in the air at 9 ft, simply let h=9 \r
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\n" ); document.write( "\n" ); document.write( "\"9=-16t%5E2%2B22t%2B5+\"\r
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\n" ); document.write( "\n" ); document.write( "\"0=-16t%5E2%2B22t-4+\" Subtract 9 from both sides\r
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\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for t:\r
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\n" ); document.write( "\n" ); document.write( "Starting with the general quadratic\r
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\n" ); document.write( "\n" ); document.write( "\"at%5E2%2Bbt%2Bc=0\"\r
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\n" ); document.write( "\n" ); document.write( "the general solution using the quadratic equation is:\r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29\"\r
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\n" ); document.write( "\n" ); document.write( "So lets solve \"-16%2At%5E2%2B22%2At-4=0\" ( notice \"a=-16\", \"b=22\", and \"c=-4\")\r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%28-22+%2B-+sqrt%28+%2822%29%5E2-4%2A-16%2A-4+%29%29%2F%282%2A-16%29\" Plug in a=-16, b=22, and c=-4\r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%28-22+%2B-+sqrt%28+484-4%2A-16%2A-4+%29%29%2F%282%2A-16%29\" Square 22 to get 484 \r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%28-22+%2B-+sqrt%28+484%2B-256+%29%29%2F%282%2A-16%29\" Multiply \"-4%2A-4%2A-16\" to get \"-256\"\r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%28-22+%2B-+sqrt%28+228+%29%29%2F%282%2A-16%29\" Combine like terms in the radicand (everything under the square root)\r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%28-22+%2B-+2%2Asqrt%2857%29%29%2F%282%2A-16%29\" Simplify the square root (note: If you need help with simplifying the square root, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%28-22+%2B-+2%2Asqrt%2857%29%29%2F-32\" Multiply 2 and -16 to get -32\r
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\n" ); document.write( "\n" ); document.write( "So now the expression breaks down into two parts\r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%28-22+%2B+2%2Asqrt%2857%29%29%2F-32\" or \"t+=+%28-22+-+2%2Asqrt%2857%29%29%2F-32\"\r
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\n" ); document.write( "\n" ); document.write( "Now break up the fraction\r
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\n" ); document.write( "\n" ); document.write( "\"t=-22%2F-32%2B2%2Asqrt%2857%29%2F-32\" or \"t=-22%2F-32-2%2Asqrt%2857%29%2F-32\"\r
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\n" ); document.write( "\n" ); document.write( "Simplify\r
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\n" ); document.write( "\n" ); document.write( "\"t=11+%2F+16-sqrt%2857%29%2F16\" or \"t=11+%2F+16%2Bsqrt%2857%29%2F16\"\r
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\n" ); document.write( "\n" ); document.write( "So these expressions approximate to\r
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\n" ); document.write( "\n" ); document.write( "\"t=0.215635347795578\" or \"t=1.15936465220442\"\r
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\n" ); document.write( "\n" ); document.write( "So our possible solutions are:\r
\n" ); document.write( "\n" ); document.write( "\"t=0.215635347795578\" or \"t=1.15936465220442\"\r
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\n" ); document.write( "\n" ); document.write( "But since we only want the height when the ball is going up, we only care about the first solution.\r
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\n" ); document.write( "\n" ); document.write( "So our solution is \"t=0.215635347795578\" which is 0.216 to the nearest thousandth
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