document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1065281>Question 1065281</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Consider a square with side of length&#8203; s, diagonal of length&#8203; d, perimeter P and area A.<BR>\n" );
document.write( "Write P as a function of s in simplified form. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #680412 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=680412\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> As I see this, P=4s<BR>\n" );
document.write( "the diagonal forms 2 right triangles.<BR>\n" );
document.write( "d^2=2s^2<BR>\n" );
document.write( "The area is s^2, the simplest way to do it.<BR>\n" );
document.write( "That is (0.5 d^2), but they don't want the area as f(diagonal) only as f(s) </SPAN>\n" );
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