document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1065267>Question 1065267</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please show the solution to this triangle problem.Show all calculations.\r<BR>\n" );
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document.write( "In triangle A,the longer leg is 6 more than the shorter leg and the hypotenuse is 6 more than the longer leg. Find the length of each side of this right triangle.\r<BR>\n" );
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document.write( "Short leg = __________  Long leg = _____________  hypotenuse = _______________\r<BR>\n" );
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document.write( "I appreciate all your freely given time and effort. Thank you very much. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #680388 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=680388\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x be the length of shorter side, then<BR>\n" );
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document.write( "longer side length is x + 6 and hypotenuse is x + 12<BR>\n" );
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document.write( "x^2 + (x+6)^2 = (x+12)^2<BR>\n" );
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document.write( "x^2 + x^2+12x+36 = x^2+24x+144<BR>\n" );
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document.write( "x^2 -12x -108 = 0<BR>\n" );
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document.write( "(x + 6) * (x - 18) = 0<BR>\n" );
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document.write( "there are two solutions, x = -6 and x = 18<BR>\n" );
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document.write( "we reject the negative length of x<BR>\n" );
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document.write( "short leg = 18<BR>\n" );
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document.write( "long leg = 24<BR>\n" );
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document.write( "hypotenuse = 30<BR>\n" );
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document.write( "note that<BR>\n" );
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document.write( "18^2 + 24^2 = 30^2<BR>\n" );
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document.write( "324 + 576 = 900<BR>\n" );
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document.write( "900 = 900<BR>\n" );
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document.write( "our answer checks<BR>\n" );
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