document.write( "Question 1065200: I'm stuck trying to prove the following inequality for positive real numbers 'n', where 'e' is a sufficiently small positive real number. Do you have a clue, technique, or reference for me to try?
\n" ); document.write( "(sqrt(n*n + e*e) - n) < (n - sqrt(n*n - e*e))
\n" ); document.write( "I came across this inequality in the study of limits.
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Algebra.Com's Answer #680375 by ikleyn(52802)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Imagine the plot of the function y = \"sqrt%28x%29\".\r\n" );
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document.write( "The difference \"sqrt%28n%5E2+%2B+e%5E2%29+-+n\" is the same as the difference \"sqrt%28n%5E2+%2B+e%5E2%29+-+sqrt%28n%5E2%29\" and is the increment \r\n" );
document.write( "of the function y = \"sqrt%28x%29\" at the point x = \"n%5E2\" when you increase the argument \"x\" by the value of \"e%5E2\".\r\n" );
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document.write( "The difference \"n+-+sqrt%28n%5E2+%2B+e%5E2%29\" is the same as the difference \"sqrt%28n%5E2%29+-+sqrt%28n%5E2+-+e%5E2%29\" and is the increment \r\n" );
document.write( "of the same function y = \"sqrt%28x%29\" at the point x = \"n%5E2-e%5E2\" when you increase the argument \"x\" by the value of \"e%5E2\".\r\n" );
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document.write( "Then your statement follows the fact that the function y = \"sqrt%28x%29\" has lower grade at the point x = \"n%5E2\" than at the point x = \"n%5E2-e%5E2\".\r\n" );
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document.write( "Very visual proof.\r\n" );
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