document.write( "Question 1065219: Franklin has $3.95 in nickels, dimes, and quarters. If he has three times as many dimes as quarters, and five fewer nickels than dimes, how many coins of each type does he have?\r
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Algebra.Com's Answer #680334 by MathTherapy(10555) $\"\"$ $\"About$

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\n" ); document.write( "Franklin has $3.95 in nickels, dimes, and quarters. If he has three times as many dimes as quarters, and five fewer nickels than dimes, how many coins of each type does he have?\r
\n" ); document.write( "\n" ); document.write( "All I have is: \r
\n" ); document.write( "\n" ); document.write( "3d=q
\n" ); document.write( "d=n-5
\n" ); document.write( "

Your equations are incorrect!
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document.write( "Let the number of quarters be Q
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document.write( "Then number of dimes = 3Q
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document.write( "Number of nickels = 3Q - 5
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document.write( "We then get: .25Q + .1(3Q) + .05(3Q - 5) = 3.95
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document.write( ".25Q + .3Q + .15Q - .25 = 3.95
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document.write( ".7Q = 3.95 + .25
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document.write( ".7Q = 4.2
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document.write( "Q, or number of quarters = 
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document.write( "Number of dimes: 
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document.write( "Number of nickels:  \n" );
document.write( "

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