document.write( "Question 1065196: How to find polynomial with solutions: (0, 2-√3, 3) ?
\n" ); document.write( "So far I did (x-0)(x+3i)(x-3i), but am not sure what to do for 2-√3. Thanks!
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Algebra.Com's Answer #680305 by ikleyn(52803)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "    How to find a polynomial with integer coefficients, having the roots 0, 2- sqrt(3) and 3 ?\r\n" );
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\n" ); document.write( "\n" ); document.write( "Such a polynomial together with the root 2-sqrt(3), must have the root 2+sqrt(3), too.\r
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document.write( "     x                 for the root 0;\r\n" );
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document.write( "     (x-(2-sqrt(3)))   for the root  (2-sqrt(3));\r\n" );
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document.write( "     (x-(2+sqrt(3)))   for the root  (2+sqrt(3));\r\n" );
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document.write( "     (x-3)             for the root 3.\r\n" );
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\n" ); document.write( "\n" ); document.write( "Thus the polynomial must be a multiple to \r
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\n" ); document.write( "\n" ); document.write( "     p(x) = x*(x(x-(2-sqrt(3)))((x-(2+sqrt(3)))*(x-3)\r
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\n" ); document.write( "\n" ); document.write( "You may write it in more convenient form.\r
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