document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1065121>Question 1065121</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One number is 3 more than twice the other number. If the sum of the two numbers is 21, find the two numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #680278 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=680278\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let A be the first number and B be the second.<BR>\n" );
document.write( "What do we know from the problem?<BR>\n" );
document.write( "A + B = 21<BR>\n" );
document.write( "A = 2B + 3<BR>\n" );
document.write( "Substitute the value of A from the second equation into the first.<BR>\n" );
document.write( "A + B = 21<BR>\n" );
document.write( "(2B+3) + B = 21<BR>\n" );
document.write( "3B + 3 = 21<BR>\n" );
document.write( "3B = 18<BR>\n" );
document.write( "Divide<BR>\n" );
document.write( "B = 6<BR>\n" );
document.write( "If B is 6, then A is \"3 more than twice\" this.  3+2(6) = 3+12 = 15<BR>\n" );
document.write( "To check the answer, put the values back into the original equation.<BR>\n" );
document.write( "Does 15 + 6 = 21? Yes<BR>\n" );
document.write( "Success! </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );