document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1065122>Question 1065122</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One number is 3 more than twice the other number. If the sum of the two numbers is 21, find the two numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #680236 by </B><A HREF=/tutors/aboutme.mpl?userid=math_helper><B>math_helper(2461)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=math_helper><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=math_helper><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=680236\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Numbers are  A and B  (let A be the larger number)\r<BR>\n" );
document.write( "\n" );
document.write( "A = 2B+3   (1)<BR>\n" );
document.write( "A+B = 21   (2)\r<BR>\n" );
document.write( "\n" );
document.write( "Subs for A in (2):   (2B+3)+B = 21<BR>\n" );
document.write( "                              3B + 3 = 21<BR>\n" );
document.write( "                               3B = 18<BR>\n" );
document.write( "                                 B = 6<BR>\n" );
document.write( "                A=2B+3 = 2(6) + 3 = 12+3 = 15\r<BR>\n" );
document.write( "\n" );
document.write( "—<BR>\n" );
document.write( "Ans:<BR>\n" );
document.write( "The numbers are 6 and 15.<BR>\n" );
document.write( "—<BR>\n" );
document.write( "Check:   6+15=21 (ok)<BR>\n" );
document.write( "             2*6+3 = 12+3 = 15 (ok)\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );