document.write( "Question 1065127: How much of a(n) 70 % orange juice drink must be mixed with 14 gallons of a 30 % orange juice drink to obtain a mixture that is 50 % orange juice? \n" ); document.write( "

Algebra.Com's Answer #680233 by math_helper(2461) $\"\"$ $\"About$

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\n" ); document.write( "We need to add X gallons of 70% drink.\r
\n" ); document.write( "\n" ); document.write( "So the amount of juice in the final mixture (14+X)(0.5) must match the amount of juice we started with (0.3*14), plus the amount of 70% to be added (0.7*X):\r
\n" ); document.write( "\n" ); document.write( "Therefore (14+X)(0.5) = (0.3)(14) + (0.7)X
\n" ); document.write( " 14+X = (0.3)(28) + (1.4)X (multiplied by 2)
\n" ); document.write( " 14+X = 8.4 + 1.4X
\n" ); document.write( " 5.6 = 0.4X
\n" ); document.write( " X = 5.6/0.4 = 14
\n" ); document.write( "--
\n" ); document.write( "Ans: Adding $\"highlight%2814%29\"$ gal of 70% drink will bring the original 14 gal 30% drink up to 50%
\n" ); document.write( "—
\n" ); document.write( "Check: (14+14)(0.5) = 14 and
\n" ); document.write( " (14)(0.3) + (14)(0.7) = 4.2 + 9.8 = 14 (ok) \n" ); document.write( "

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