document.write( "Question 1065076: If nine software engineers were interviewed to develop an estimate for software lines of code. The mean estimate is 12480 lines of code with a standard deviation of 2000 lines of code. Develop a 90 per cent confidence interval for the population mean. Carry to three decimal places\r
\n" );
document.write( "\n" );
document.write( "Would the correct answer be 10992 13968 \n" );
document.write( "
Algebra.Com's Answer #680230 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! The sample mean is 12480 and the sample standard deviation is 2000 \n" ); document.write( ": \n" ); document.write( "We want a 90% confidence interval for the population mean \n" ); document.write( ": \n" ); document.write( "alpha(a) is 1 - (90/100) = 0.10 \n" ); document.write( ": \n" ); document.write( "critical probability(p*) = 1 - (a/2) = 0.95 \n" ); document.write( ": \n" ); document.write( "because our sample size is < 30, we use the t-statistic \n" ); document.write( ": \n" ); document.write( "degrees of freedom = 9 - 1 = 8 \n" ); document.write( ": \n" ); document.write( "we lookup in the students t-table the critical value(CV) that has 8 degrees of freedom and a p* of 0.95 \n" ); document.write( ": \n" ); document.write( "CV is 1.860 \n" ); document.write( ": \n" ); document.write( "margin of error(ME) = CV * standard deviation = 1.860 * 2000 = 3720 \n" ); document.write( ": \n" ); document.write( "*********************************************************** \n" ); document.write( "95% confidence interval = 12480 + or - 3720 = (8760, 16200) \n" ); document.write( "*********************************************************** \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( " |