document.write( "Question 1065076: If nine software engineers were interviewed to develop an estimate for software lines of code. The mean estimate is 12480 lines of code with a standard deviation of 2000 lines of code. Develop a 90 per cent confidence interval for the population mean. Carry to three decimal places\r
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Algebra.Com's Answer #680230 by rothauserc(4718)\"\" \"About 
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The sample mean is 12480 and the sample standard deviation is 2000
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\n" ); document.write( "We want a 90% confidence interval for the population mean
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\n" ); document.write( "alpha(a) is 1 - (90/100) = 0.10
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\n" ); document.write( "critical probability(p*) = 1 - (a/2) = 0.95
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\n" ); document.write( "because our sample size is < 30, we use the t-statistic
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\n" ); document.write( "degrees of freedom = 9 - 1 = 8
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\n" ); document.write( "we lookup in the students t-table the critical value(CV) that has 8 degrees of freedom and a p* of 0.95
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\n" ); document.write( "CV is 1.860
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\n" ); document.write( "margin of error(ME) = CV * standard deviation = 1.860 * 2000 = 3720
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\n" ); document.write( "95% confidence interval = 12480 + or - 3720 = (8760, 16200)
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