document.write( "Question 1065085: A train leaves San Diego at 1:00PM. A second train leaves the same city in the same direction at 4:00PM. The second train travels 78mph faster than the first. If the second train overtakes the first at 6:00PM, what is the speed of each of the two trains? \n" ); document.write( "

Algebra.Com's Answer #680215 by ikleyn(53764) $\"\"$ $\"About$

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\n" ); document.write( "A train leaves San Diego at 1:00PM. A second train leaves the same city in the same direction at 4:00PM.
\n" ); document.write( "The second train travels 78mph faster than the first. If the second train overtakes the first at 6:00PM,
\n" ); document.write( "what is the speed of each of the two trains?
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document.write( "Let \"v\" be the speed of the first train (in mph);\r\n" );
document.write( "then the speed of the second train is (v+78) mph, according to the condition.\r\n" );
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document.write( "Now, the distance traveled by the first train till the overtaking moment was 5v miles, where 5 is/are 5 hours from 1:00 pm till 6:00 pm.\r\n" );
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document.write( "The distance traveled by the second train till the overtaking moment was 2*(v+78) miles, where 2 is/are 2 hours from 4:00 pm till 6:00 pm.\r\n" );
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document.write( "The distance is the same, which gives you an equality\r\n" );
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document.write( "5v = 2(v+78).\r\n" );
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document.write( "Simplify and solve for \"v\":\r\n" );
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document.write( "5v = 2v + 156  ---->  3v = 156  ---->  v =  = 52.\r\n" );
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document.write( "Answer. The speed of the first train was 52 mph. The speed of the second train was 52 + 78 = 130 mph.\r\n" );
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